PROBLEMAS ALGEBRAICOS SENCILLOS

Problemas

a = 3 b = c = 5

a² + b = 13
(3)² + b = 13
a + b = 13
b + 13 – 9
b = 4

a 4c/b =8
3 + 4(5)/b = 8
4 (5)/b = 8 – 3
20/b = 5
20 = 5b
5b = 20
b = 4

X vale 2

6x³ + 9x² + 3x/3x =
Simplifico y luego sustituyo
2x² + 3x + 1 =
2 (4) + 6 + 1 =
8 + 6 + 1 = 15